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First solution in 3rd party category for Pawn Brotherhood by Geovanna_M_Gomez
import numpy as np
def safe_pawns(pawns):
d={'a':0,'b':1,'c':2,'d':3,'e':4,'f':5,'g':6,'h':7}
tablero= np.zeros((8,8))
for coordenada in pawns:
i= 8-int(coordenada[1])
j=d[coordenada[0]]
tablero[i,j]= 1
contador=0
f,c = tablero.shape
for i in range(f):
for j in range(c):
if tablero[i,j]==1:
if tablero[i+1:i+2 , j-1:j]==1 or tablero[i+1:i+2 , j+1:j+2]==1:
contador+=1
return contador
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Jan. 19, 2017
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