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Weird one-liner solution in Speedy category for Pawn Brotherhood by Gabbek
def safe_pawns(pawns):
return sum((any(chr(ord(l) + i) + str(int(d) - 1) in pawns for i in [-1, 1])) for l, d in pawns)
if __name__ == '__main__':
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
June 4, 2016
