First - Pawn Brotherhood clear solution for Pawn Brotherhood by AQiccl135 - python coding challenges

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First - Pawn Brotherhood solution in Clear category for Pawn Brotherhood by AQiccl135

FILES = "abcdefgh"
def safe_pawns(pawns):
    # Start with zero safe pawns, then check each pawn
    safe = 0
    for each in pawns:
        # This really should say "> 2", but some of the pawns have moved back a
        # rank
        if int(each[1]) > 1:
            # Checks if any of the positions that can protect a pawn are occupied
            if any(every in pawns for every in get_protectors(each[0], int(each[1]))):
                safe += 1
    return safe

def get_protectors(file, rank):
    file_index = FILES.index(file)
    row_below = str(rank - 1)
    # Gets both protectors if the pawn is not on the edge of the board ...
    if file in FILES[1:-1]:
        protectors = [FILES[file_index - 1] + row_below, FILES[file_index + 1] + row_below]
    # ... or the only protector if the pawn is on an edge
    elif file == 'a':
        protectors = ['b' + row_below]
    else:
        protectors = ['g' + row_below]
    return protectors

Oct. 31, 2014

Comments:

juhokarppinen on April 26, 2015, 11:06 a.m.
<p>This implementation is somewhat difficult to read and could be condensed within a single function.</p>

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