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Cube rotation solution in Clear category for Paper Dice by tom-tom
def paper_dice(paper):
cells = {(x, y): int(value) for y, row in enumerate(paper)
for x, value in enumerate(row) if value != ' '}
def rotate(cube, s):
sx, sy = s
return {((-z * sx, y, x * sx), (x, -z * sy, y * sy))[sy != 0]: value
for (x, y, z), value in cube.items()}
def mark(cube, pos):
cube[(0, 0, 1)] = cells[pos]
del cells[pos]
for s in (1, 0), (-1, 0), (0, 1), (0, -1):
new_pos = pos[0] + s[0], pos[1] + s[1]
if new_pos in cells:
cube = rotate(mark(rotate(cube, s), new_pos), (-s[0], -s[1]))
return cube
cube = mark({}, next(iter(cells)))
return (len(cube) == 6 and
cube[(1, 0, 0)] + cube[(-1, 0, 0)] ==
cube[(0, 1, 0)] + cube[(0, -1, 0)] ==
cube[(0, 0, 1)] + cube[(0, 0, -1)] == 7)
July 23, 2019
