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First solution in Clear category for Pangram by m.dziardziel
def check_pangram(text):
text=text.lower()
lista=[0,0]
for a in range(0,250):
lista.append(0)
for a in text:
lista[ord(a)]=lista[ord(a)]+1
for a in range(97,123):
if lista[a]==0:
return False
return True
Nov. 16, 2016
