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First solution in Creative category for Pangram by krzysztofc10
def check_pangram(text):
text=text.lower()
counter=0
for i in range(97,123):
if chr(i) in text:
counter+=1
if counter==26:
return True
#lese
else:
return False
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
print('If it is done - it is Done. Go Check is NOW!')
Jan. 16, 2018
