Pangram uncategorized solution for Pangram by capback250 - python coding challenges

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Pangram solution in Uncategorized category for Pangram by capback250

def check_pangram(text):
    d = dict()
    for c in text.lower():
        if c.isalpha():
            if c not in d:
                d[c] = 1
            else:
                d[c] = d[c] + 1
        else:
            continue

    return True if len(d) == 26 else False

if __name__ == '__main__':
    # These "asserts" using only for self-checking and not necessary for auto-testing
    assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
    assert not check_pangram("ABCDEF"), "ABC"
    assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"

Aug. 1, 2015

Comments:

Moff on Aug. 2, 2015, 2:35 p.m.
<p>replace last if statement by simple boolean expression</p>

capback250 on Aug. 2, 2015, 5:51 p.m.
<p>Moff, mersi! Now my code a bit closer to python beauty :) </p> <pre class='brush: python'>class Chekio(object): @staticmethod def check_pangram(text): d = dict() for c in text.lower(): if c.isalpha(): if c not in d: d[c] = 1 else: d[c] = d[c] + 1 else: continue return len(d) == 26 </pre>

Strings Theory

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