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First solution in Clear category for Pangram by artur_mierzwa
def check_pangram(text):
t=""
x= sorted("".join(text.lower().split()))
for i in range(len(x)):
if x[i]!= x[i-1] and (x[i].isalpha()):
t+=x[i]
z= "abcdefghijklmnopqrstuvwxyz"
if t==z:
return True
else:
return False
Oct. 31, 2016
