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First solution in Clear category for Pangram by PythOff
def check_pangram(text):
tab = []
for i in range (26):
tab.append(0)
dl = len(text)
if dl < 26:
return False
for i in range(dl):
if str(text[i]) >= 'a' and str(text[i]) <= 'z':
tab[ord(text[i]) - ord('a')] = 1
if str(text[i]) >= 'A' and str(text[i]) <= 'Z':
tab[ord(text[i]) - ord('A')] = 1
return sum(tab) == 26
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Nov. 10, 2016
