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First solution in Clear category for Pangram by KarolinaK
def check_pangram(text):
p=""
letters=[0]*26
print(letters)
for i in text:
if(ord(i)>64 and ord(i)<91) or (ord(i)>96 and ord(i)<123):
p+=i.upper()
letters[ord(p[len(p)-1])-65]+=1
print(letters)
for i in letters:
if i==0:
return False
#print(p)
return True
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Nov. 10, 2016
