Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Pangram by Andreas_Strus
def check_pangram(text):
a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
d = 0
text = text.replace(' ', '')
text = text.lower()
for n in a:
print(n)
print(text.count(n))
if text.count(n) >= 1:
d = d + 1
if d == len(a):
return True
return False
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Oct. 26, 2016
