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First solution in Clear category for Number Base by matesik1995
def checkio(str_number, radix):
s=0
for a in reversed(range(len(str_number))):
n=0
if str_number[a].isdigit():
n=int(str_number[a])
else:
n=ord(str_number[a])-ord('A')+10
if n < radix:
s+=n*radix**(len(str_number)-a-1)
else:
return -1
return s
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("AF", 16) == 175, "Hex"
assert checkio("101", 2) == 5, "Bin"
assert checkio("101", 5) == 26, "5 base"
assert checkio("Z", 36) == 35, "Z base"
assert checkio("AB", 10) == -1, "B > A > 10"
Nov. 28, 2016
