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First solution in Clear category for Numbers Factory by matesik1995
def checkio(number):
res = []
while number > 1:
did=False
for i in reversed(range(2,10)):
if number%i==0:
number/=i
res.append(i)
did=True
break
if not did:
return 0
res.sort()
ret=0
for i in range(len(res)):
ret+=res[i]*10**(len(res)-i-1)
return ret
"""
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(20) == 45, "1st example"
assert checkio(21) == 37, "2nd example"
assert checkio(17) == 0, "3rd example"
assert checkio(33) == 0, "4th example"
assert checkio(3125) == 55555, "5th example"
assert checkio(9973) == 0, "6th example"
"""
Nov. 29, 2016
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