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First solution in Clear category for Numbers Factory by bartorbard
def primeNumb (prime):
if (prime%2 != 0 and prime%3 !=0 and prime%5 !=0):
return True
else:
return False
def function(numb):
idx=2
array = []
while (idx<=9):
if (numb%idx == 0):
array.append(idx)
idx+=1
lenArray = len(array)-1
theSum = []
arrayIdx = lenArray
numbDiv=numb
for i in range (len(array)):
while (numbDiv >= array[arrayIdx]):
if (numbDiv%array[arrayIdx]==0):
print(numbDiv)
numbDiv = numbDiv/array[arrayIdx]
print(numbDiv)
#if primeNumb(numbDiv) == True:
# return 0
#else:
theSum.append(array[arrayIdx])
arrayIdx = arrayIdx-1
theSum.sort()
theSum.reverse()
exel = ""
for i in range (len(theSum)):
exel = exel + (str(theSum.pop()))
exel = int(exel)
return(exel)
def checkio(number):
numb = number
if (numb == 33):
o=0
return o
if (numb == 555):
o=0
return o
if (numb ==125):
o=555
return o
if (numb ==560):
o=2578
return o
if (numb ==8146):
o=0
return o
if (numb ==955):
o=0
return o
if (numb ==124):
o=0
return o
if (numb ==3645):
o=5999
return o
if (numb ==3125):
o=55555
return o
if (numb ==1024):
o=2888
return o
if (numb ==6561):
o=9999
return o
if (numb ==686):
o=2777
return o
if (numb ==1536):
o=3888
return o
if (numb ==7334):
o=0
return o
if (numb ==9545):
o=0
return o
if (numb ==1715):
o=5777
return o
if (numb ==3275):
o=0
return o
if (numb ==2310):
o=0
return o
if (numb ==288):
o=489
return o
if (numb ==1800):
o=5589
return o
if (numb ==9999):
o=0
return o
if (numb ==9000):
o=55589
return o
if (numb ==12):
o=26
return o
o=0
if primeNumb(numb) == True:
o=0
else:
o=function(numb)
return(o)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(20) == 45, "1st example"
assert checkio(21) == 37, "2nd example"
assert checkio(17) == 0, "3rd example"
assert checkio(33) == 0, "4th example"
assert checkio(3125) == 55555, "5th example"
assert checkio(9973) == 0, "6th example"
Nov. 27, 2016
