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Number Factory task solution in Clear category for Numbers Factory by Fokzterrier
def checkio(N):
X = []
k = N
while k>1:
if k%9==0:
X.append(9)
k= k/9
elif k%8==0:
X.append(8)
k= k/8
elif k%7==0:
X.append(7)
k= k/7
elif k%6==0:
X.append(6)
k=k/6
elif k%5==0:
X.append(5)
k=k/5
elif k%4==0:
X.append(4)
k=k/4
elif k%3==0:
X.append(3)
k=k/3
elif k%2==0:
X.append(2)
k=k/2
else:
X=0
return X
X.sort()
print(X)
s = ''.join(map(str, X))
return int(s)
Nov. 1, 2016