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easy solution in Clear category for Non-unique Elements by sputnik51
# Your optional code here
# You can import some modules or create additional functions
def checkio(data: list) -> list:
# Your code here
# It's main function. Don't remove this function
# It's used for auto-testing and must return a result for check.
# replace this for solution
return [x for x in data if data.count(x) > 1]
# Some hints
# You can use list.count(element) method for counting.
# Create new list with non-unique elements
# Loop over original list
if __name__ == "__main__":
# These "asserts" using only for self-checking and not necessary for auto-testing
assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example"
assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example"
assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example"
assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example"
print("It is all good. Let's check it now")
May 16, 2021
