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lambda solution in Clear category for Non-unique Elements by Max0526
checkio = lambda data : [x for x, c in zip(data, map(data.count, data)) if c > 1]
'''
A rewrite of
def checkio(data: list) -> list:
if len(data) == 0: return []
count = []
for i in range(len(data)): c = data.count(data[i]); count.append(c)
i = 0; l = len(data)
while i < l:
if count[i] == 1: del data[i]; del count[i]; l -= 1
else: i += 1
return data
'''
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example"
assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example"
assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example"
assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example"
print("It is all good. Let's check it now")
May 1, 2023
