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Non-unique Elements solution in Speedy category for Non-unique Elements by JimmyCarlos
def checkio(A):
singles = set()
doubles = set()
for a in A:
if a not in singles: singles.add(a)
else: doubles.add(a)
return [a for a in A if a in doubles]
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example"
assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example"
assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example"
assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example"
print("It is all good. Let's check it now")
July 25, 2018
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