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collections.Counter solution in Clear category for The Most Wanted Letter by rrr
from collections import Counter
from string import ascii_lowercase as lo
def checkio(text):
c = Counter()
for letter in filter(lambda l: l in lo, text.lower()):
c[letter] += 1
best = max(c[letter] for letter in c)
return sorted(letter for letter in c if c[letter] == best)[0]
Dec. 25, 2014
