First clear solution for The Most Wanted Letter by masero - python coding challenges

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First solution in Clear category for The Most Wanted Letter by masero

def checkio(text):
    text = text.lower()
    M = [0]*26
    N=[]
    for char in text:
        if ord(char) in range(97,123):
            M[ord(char)-97]+=1
    for i,elt in enumerate(M):
        if elt == max(M):
            N.append(i)
    return chr(min(N)+97)

Aug. 6, 2014

Comments:

dan.garthwaite on Aug. 29, 2014, 4:40 p.m.
Program C much? :)

lisfer on May 21, 2018, 8:30 p.m.
Interesting solution. Just want to mention - moving `range(97, 123)` out of the loop - is a good approach (for performance). Same thing with `max(M)` function. Also, it's better to replace a couple of calls `ord(char)` with a single one. These three simple steps will increase our performance more than twice (according to my tests): ~5.7 seconds (per 100 000 operations for base code) and ~2.6 for refactored: <pre class='brush: python'>def checkio6(text): text = text.lower() M = [0]*26 N = [] letters = range(97,123) for char in text: ord_char = ord(char) if ord_char in letters: M[ord_char-97]+=1 max_val = max(M) for i,elt in enumerate(M): if elt == max_val: N.append(i) return chr(min(N)+97) </pre>

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