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First solution in Clear category for The Most Wanted Letter by masero
def checkio(text):
text = text.lower()
M = [0]*26
N=[]
for char in text:
if ord(char) in range(97,123):
M[ord(char)-97]+=1
for i,elt in enumerate(M):
if elt == max(M):
N.append(i)
return chr(min(N)+97)
Aug. 6, 2014
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