First clear solution for The Most Wanted Letter by jollyca - python coding challenges

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First solution in Clear category for The Most Wanted Letter by jollyca

def checkio(text):
    """ Find the most frequent letter in an expression
        Based on the algorithms used at http://rosettacode.org/wiki/Letter_frequency
    """
     
    # Edge case - one letter.
    if len(text)==1 and ord(text) in range(ord('a'),ord('z')+1):
        return text
     
    # choose only the letters from the text
    new_string = [letter for letter in text.lower() if ord(letter) in range(ord('a'),ord('z')+1)]
    new_string = ''.join(new_string)
    
    # define a list of frequencies
    freqs = [0 for i in range(0,26)]
   
    for letter in new_string:
        # increase the frequency for the corresponding letter
        freqs[ord(letter)-ord('a')]+=1
        
    # choose the maximum value from the frequencies
    max_value = max(freqs)
    # determine the index of the maximum value
    max_index = sorted([index for index, value in enumerate(freqs) if value == max_value])
    
    # determine the letter corresponding to the index and return
    return (chr(ord('a') + max_index[0]))

#These "asserts" using only for self-checking and not necessary for auto-testing

April 24, 2014

Comments:

selfDev21 on June 29, 2016, 9:59 p.m.
<p>Reading your code reminds me of when I did C. Specifically, the increase the frequency for the corresponding letter loop.</p>

Strings and Integers

0 %

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