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First solution in Clear category for The Most Wanted Letter by Vesemir
def checkio(text):
text = text.lower()
text = sorted(text)
best_freq = 0
best_char = ""
for c in text:
if text.count(c) > best_freq and c.isalpha():
best_freq = text.count(c)
best_char = c
return best_char
April 27, 2015
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