Second creative solution for The Most Wanted Letter by Tinus_Trotyl - python coding challenges

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Second solution in Creative category for The Most Wanted Letter by Tinus_Trotyl

def checkio(text):
    r = {c: text.lower().count(chr(c)) for c in range(97, 123)}
    return chr(max(r, key=r.__getitem__ ))

Aug. 18, 2017

Comments:

Grunwalski on March 26, 2018, 10:46 a.m.
why 97 and 123 ?

Tinus_Trotyl on March 26, 2018, 12:59 p.m.
Hi, <pre class='brush: python'>ord('a') == 97</pre> thus: <pre class='brush: python'>chr(97) == 'a'</pre>, <pre class='brush: python'>chr(98) == 'b'</pre>, <pre class='brush: python'>chr(99) == 'c'</pre> etc .... So ... knowing this now, you can "generate" the lower case alphabet by <pre class='brush: python'>chr(c) for c in range(97, 123)</pre> , you see ? :-)

songbai121 on Aug. 24, 2018, 12:01 a.m.
Thanks, I only knew how to make list from iteration. Now I know more!

Strings and Integers

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