Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Simple solution in Clear category for The Most Wanted Letter by Sisyphus
def checkio(text):
stripped = [c.lower() for c in text if 'a'<=c<='z' or 'A'<=c<='Z']
counts = {c:stripped.count(c) for c in set(stripped)}
return max(sorted(counts), key=counts.get)
Nov. 26, 2015
Comments: