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+ regular (re.)+sort by abc (with self made func return x[0]), max(key str.count) solution in Clear category for The Most Wanted Letter by SHAKHRUKHIRGASHEV
import re
def kek(x):
return x[0]
def checkio(text: str) -> str:
text = (''.join(i for i in text if not i.isdigit()))
pat = r'\w'
a = sorted(re.findall(pat,text.lower()),key=kek)
return max(a,key=a.count)
if __name__ == '__main__':
print("Example:")
print(checkio("Hello World!"))
print(checkio("AAaooo!!!!"))
print(checkio('One'))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
June 5, 2022
