Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
walrus lambda one-liner solution in Clear category for The Most Wanted Letter by Max0526
checkio = lambda str: (
dct := {char: str.lower().count(char) for char in str.lower() if char.isalpha()},
min(dct, key = lambda k: (-dct[k], k))
)[1]
'''
A rewrite of
def checkio(t: str) -> str:
d = {l : t.lower().count(l) * l.isalpha() for l in t.lower()}; \
return list(sorted({k : '' for k, v in dict.items(d) if v == max(dict.values(d))}))[0]
'''
Nov. 3, 2025
