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First solution in Clear category for The Most Wanted Letter by Degusto
def checkio(text):
text = text.lower()
max = {'letter':'a','count':0}
for letter in text:
if text.count(letter) > max['count'] and (letter >= 'a' and letter <= 'z'):
max['count'] = text.count(letter)
max['letter'] = letter
if text.count(letter) == max['count'] and (letter >= 'a' and letter <= 'z') and letter < max['letter']:
max['letter'] = letter
return max['letter']
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Nov. 17, 2015
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