dict + groupby clear solution for Most Wanted Letter by kdim - python coding challenges

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dict + groupby solution in Clear category for Most Wanted Letter by kdim

import itertools
def most_wanted(text: str) -> str:
    d = dict([(k, len(list(g))) for k, g in itertools.groupby(sorted(text.lower())) if 'a' <= k <= 'z'])
    return [k for k, v in d.items() if v == max(d.values())]

Jan. 26, 2021

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