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First solution in Clear category for The Most Numbers by Rafal__Kotas
def checkio(*args):
max = 0.2 - 2000000.2
min = 1000000000.01
if(len(args)>0):
for x in args:
if(float(x)max):
max = float(x)
return (max-min)
else:
return 0
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
Nov. 1, 2016
