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First solution in Clear category for Min and Max by saklar13
def min(*args, key=None):
if len(args) == 1: args = args[0]
return sorted(args, key=key)[0]
def max(*args, key=None):
if len(args) == 1: args = args[0]
return sorted(args, key=key, reverse=True)[0]
Jan. 7, 2015
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