Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Min and Max by PawelMartyniuk
def min(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
items = args[0] if len(args) == 1 else args[:]
min_value = None
for i in items:
if min_value is None:
min_value = i
min_value = i if key(i) < key(min_value) else min_value
return min_value
def max(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
items = args[0] if len(args) == 1 else args[:]
max_value = None
for i in items:
if max_value is None:
max_value = i
max_value = i if key(i) > key(max_value) else max_value
return max_value
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Nov. 6, 2016