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First solution in Clear category for Min and Max by Bartek.Knobel
def min(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
licz = args[0] if len(args) == 1 else args[:]
mini = None
for i in licz:
if mini is None:
mini = i
mini = i if key(i) < key(mini) else mini
return mini
def max(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
licz = args[0] if len(args) == 1 else args[:]
maxi = None
for i in licz:
if maxi is None:
maxi = i
maxi = i if key(i) > key(maxi) else maxi
return maxi
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Nov. 9, 2016
