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First solution in Clear category for Middle Characters by Sheldon488
def middle(text: str) -> str:
n = len(text)
mid = n // 2
if n % 2 == 1: # odd length → 1 middle character
return text[mid]
else: # even length → 2 middle characters
return text[mid - 1 : mid + 1]
Dec. 1, 2025
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