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First solution in Clear category for Median by Piotr.Helminiak
def checkio(data):
a=sorted(data)
l=len(data)
if l%2:
return a[int(l/2)]
else:
return (a[int(l/2)-1]+a[int(l/2)])/2
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
print("Start the long test")
assert checkio(list(range(1000000))) == 499999.5, "Long."
print("The local tests are done.")
Nov. 8, 2016
