First clear solution for Pattern Recognition by fleo0917 - python coding challenges

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First solution in Clear category for Pattern Recognition by fleo0917

def checkio( A, B) :
    for i in range(len(B)) :
        for j in range(len(B[0])) :
            try :
                if all( A[k][l] == B[i+k][j+l] for k in range(len(A)) for l in range(len(A[0]))) :
                    for k in range(len(A)) :
                        for l in range(len(A[0])) :
                            B[i+k][j+l] += 2
            except :
                pass
    return B

Jan. 26, 2015

Comments:

Pouf on July 14, 2020, 5:06 p.m.
<p><pre class='brush: python'>except IndexError:</pre> would be preferable here, it would give a clue as to why there is a <pre class='brush: python'>try except</pre> (to avoid having to care about "out of bounds"). And it's a good habit to never let anything that you didn't think about <pre class='brush: python'>pass</pre>. It shields your function against funny cases where A or B is not a list of list of ints. It is then easier to debug, because you have a traceback.</p> <p>Also now when you just have an <pre class='brush: python'>except: pass</pre> you can use <pre class='brush: python'>with contextlib.suppress(IndexError):</pre></p>

Blizzard

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