Second clear solution for Long Repeat by fed.kz - python coding challenges

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Second solution in Clear category for Long Repeat by fed.kz

long_repeat=lambda l,g=__import__('itertools').groupby: max(len(list(x))for _,x in g(l))if l else 0

Oct. 11, 2018

Comments:

w78Rq on Oct. 27, 2018, 12:02 p.m.
one string...yeah

kirosx88 on Nov. 25, 2018, 3:04 p.m.
I don't know what is that means, but i'm impressed))

fed.kz on Nov. 25, 2018, 5:43 p.m.
I apply the <pre class='brush: python'>groupby</pre> function to the string. It forms an iterable object of the form <pre class='brush: python'>[element, elements going in a row]</pre>. Next, I am find the maximum of length the elements in a row. On example: <pre class='brush: python'>[[x, list(y)] for x, y in groupby('aaabbCcc')] == [['a', ['a', 'a', 'a']], ['b', ['b', 'b']], ['C', ['C']], ['c', ['c', 'c']]] </pre> Maximum length of this: <pre class='brush: python'>len(['a', 'a', 'a']) == 3</pre>

Strings Theory

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