Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Groupby oneliner solution in Clear category for Long Repeat by SasuH
from itertools import groupby
def long_repeat(line: str) -> int:
"""
length the longest substring that consists of the same char
"""
# your code here
return max([0]+[len(list(group[1])) for group in groupby(line)])
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert long_repeat('sdsffffse') == 4, "First"
assert long_repeat('ddvvrwwwrggg') == 3, "Second"
assert long_repeat('abababaab') == 2, "Third"
assert long_repeat('') == 0, "Empty"
print('"Run" is good. How is "Check"?')
Jan. 17, 2021
