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len, default solution in Clear category for Long Non Repeat by akaka
def non_repeat(d):
return max([d[s:s+e] for s in range(len(d)) for e in range(1,len(d)+1)
if all(d[s:s+e].count(x)<2 for x in d[s:s+e])],
key=len,default="")
Oct. 25, 2018
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