SIMPLE clear solution for Leap Year Checking by U.V - python coding challenges - Py.CheckiO

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SIMPLE solution in Clear category for Leap Year Checking by U.V

def is_leap_year(year: int) -> bool:
    if year%4:return False
    if year%100:return True
    return year%400==0

Jan. 1, 2024

Strings and Integers

0

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