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Very simple implementation solution in Clear category for Largest Rectangle in a Histogram by mindaugas.dadurkevicius
def largest_histogram(histogram):
max = 0
for i in range(len(histogram)):
for i2 in range(i, len(histogram)):
if min(histogram[i:i2+1]) * (i2 - i + 1) > max:
max = min(histogram[i:i2+1]) * (i2 - i + 1)
return max
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert largest_histogram([5]) == 5, "one is always the biggest"
assert largest_histogram([5, 3]) == 6, "two are smallest X 2"
assert largest_histogram([1, 1, 4, 1]) == 4, "vertical"
assert largest_histogram([1, 1, 3, 1]) == 4, "horizontal"
assert largest_histogram([2, 1, 4, 5, 1, 3, 3]) == 8, "complex"
print("Done! Go check it!")
July 13, 2018
