First clear solution for Index Power by diwert-ai - python coding challenges

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First solution in Clear category for Index Power by diwert-ai

def index_power(array: list, n: int) -> int:
    return array[n]**n if n < len(array) else -1

print('Example:')
print(index_power([1, 2, 3], 2))

assert index_power([1, 2, 3, 4], 2) == 9
assert index_power([1, 3, 10, 100], 3) == 1000000
assert index_power([0, 1], 0) == 1
assert index_power([1, 2], 3) == -1

print("The mission is done! Click 'Check Solution' to earn rewards!")

Aug. 23, 2022

Comments:

MarHar on Nov. 12, 2022, 6:01 p.m.
<p>Interesting -- I love how this is all in one line. My code tends to get packed with if and else blocks.</p>

diwert-ai on Nov. 13, 2022, 2:14 p.m.
<p>Thanks fo review! At first, syntactic sugar is difficult to perceive. Then you get used to it and start only writing the code as concisely as possible, as python allows. That's why we love python =)</p>

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