(em)powering creative solution for Index Power by ale1ster - python coding challenges

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(em)powering solution in Creative category for Index Power by ale1ster

def index_power(ra, n):
    return {i: ra[i]**i for i in range(len(ra))}.get(n, -1)

Sept. 3, 2014

Comments:

marius_eduard on Sept. 3, 2014, 6:33 a.m.
Nice! Can you explain the code?

ale1ster on Sept. 3, 2014, 7:34 a.m.
Create a dict, mapping indices on the given array to the requested powers (element ** index). Then you simply get() the element from the requested index, defaulting to -1 if the mapping doesn't exist in the dictionary.

marius_eduard on Sept. 4, 2014, 7:52 a.m.
Smart solution. Thanks!

ale1ster on Sept. 4, 2014, 1:03 p.m.
Maybe, but not efficient :-) For efficiency check the try-except ones...

StefanPochmann on April 20, 2015, noon
Nice one, although using <pre class='brush: python'>enumerate</pre> would've been better.

ale1ster on June 5, 2015, 12:52 p.m.
I think you are right :P

ludek.reif on Feb. 2, 2016, 6:35 a.m.
Nice solution.

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