CNF creative solution for House Password by veky - python coding challenges

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CNF solution in Creative category for House Password by veky

checkio=lambda d:9
                        Sept. 28, 2014

                        
                            Comments:
                            
                                
                                    smjefferson602
 on Sept. 28, 2014, 11:40 p.m.

                                    <p>man, comprehensions still seem like magic to me! :{)</p>

                                
                            
                                
                                    veky
 on Sept. 28, 2014, 11:50 p.m.

                                    <p>Not magic, just illusionism, as I like to say. :-)</p>

<p>Write code, see what's repeated, factor it out; whatever is left, put it in sequence to iterate through. Simple. :-)</p>

<p>Of course, I could factor out even more:</p>

<pre class='brush: python'>any(map(getattr(str, "is" + t), d)) for t in "digit upper lower".split()
</pre>

<p>But then it'd be too long. ;-]</p>

                                
                            
                                
                                    xiaozhan
 on Nov. 11, 2015, 7:19 a.m.

                                    <p>Mine <a href="http://www.checkio.org/mission/house-password/publications/xiaozhan/python-3/first/">here</a>.</p>

                                
                            
                                
                                    petrch
 on Sept. 17, 2017, 9:46 a.m.

                                    <p>am I right that this only works because of the precondition re.match("[a-zA-Z0-9]+", password)? otherwise I like it as an alternative to the regex solution with forward lookups.</p>

                                
                            
                                
                                    veky
 on Sept. 24, 2018, 8:28 a.m.

                                    <p>It quite literally checks whether the password has length greater than 9, and whether it contains a digit, an uppercase character, and a lowercase character. What more would you want? :-)</p>

                                
                            
                                
                                    bsquare
 on Sept. 18, 2019, 9:42 a.m.

                                    <p>Haha! At first it is like Vodoo ... then it is obvious talent;)</p>

<p>Thanks for your solutions:)</p>

                                
                            
                                
                                    veky
 on Sept. 18, 2019, 9:44 a.m.

                                    <p>If you know Conjunctive Normal Form from logic, it shouldn't be so surprising. :-)</p>

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