tricky clear solution for House Password by bbmin7b5 - python coding challenges

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tricky solution in Clear category for House Password by bbmin7b5

import re

def checkio(password):
    match = re.search(r"[a-z]+", password)
    match1 = re.search(r"[A-Z]+", password)
    match2 = re.search(r"[0-9]+", password)
    if len(password) >= 10 and match and match1 and match2:
        return True
    else:
        return False
#Some hints
#Just check all conditions


if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert checkio('A1213pokl') == False, "1st example"
    assert checkio('bAse730onE4') == True, "2nd example"
    assert checkio('asasasasasasasaas') == False, "3rd example"
    assert checkio('QWERTYqwerty') == False, "4th example"
    assert checkio('123456123456') == False, "5th example"
    assert checkio('QwErTy911poqqqq') == True, "6th example"

Sept. 24, 2014

Comments:

Bivvy on Jan. 2, 2015, 2:48 p.m.
Solution easy to follow

bbmin7b5 on Feb. 15, 2015, 12:16 a.m.
Thanks!

jgo3000 on March 22, 2015, 9:02 a.m.
Interesting. I am not familiar with the re module and therefore re.search(). It certainly makes your code very straight forward and readable. Nice job.

bbmin7b5 on March 22, 2015, 8:20 p.m.
Thank you sir. I love using the RE module. It's very helpful when searching for text.

suic on May 25, 2015, 8:20 p.m.
Hi, lot of redundancy there <ol> <li>that `if...else` is redundant: return len(password) >= 10 and match and match1 and match2</li> <li>Or lines 4-6 contains the same pattern.</li> </ol>

Strings Theory

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