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First solution in Clear category for The Hamming Distance by janusztracz73ms
def checkio(n, m):
n = bin(n)[2:]
m = bin(m)[2:]
if len(n) > len(m):
m = m.zfill(len(n))
else:
n = n.zfill(len(m))
total = 0
for x in range(len(n)):
if n[x] != m[x]:
total += 1
return total
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(117, 17) == 3, "First example"
assert checkio(1, 2) == 2, "Second example"
assert checkio(16, 15) == 5, "Third example"
Nov. 25, 2016