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First solution in Clear category for Group Equal consecutive by zaviskapavel
def group_equal(els):
output = []
cnt = -1
el_old = None
for el in els:
if el != el_old:
output.append([])
cnt += 1
output[cnt].append(el)
else:
output[cnt].append(el)
el_old = el
return output
if __name__ == '__main__':
print("Example:")
print(group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]) == [[1, 1], [4, 4, 4], ["hello", "hello"], [4]]
assert group_equal([1, 2, 3, 4]) == [[1], [2], [3], [4]]
assert group_equal([1]) == [[1]]
assert group_equal([]) == []
print("Coding complete? Click 'Check' to earn cool rewards!")
June 11, 2019
