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First solution in Clear category for Group Equal consecutive by vtflnk
from itertools import groupby
def group_equal(els):
return [list(group) for _, group in groupby(els)]
if __name__ == "__main__":
print("Example:")
print(group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]) == [
[1, 1],
[4, 4, 4],
["hello", "hello"],
[4],
]
assert group_equal([1, 2, 3, 4]) == [[1], [2], [3], [4]]
assert group_equal([1]) == [[1]]
assert group_equal([]) == []
print("Coding complete? Click 'Check' to earn cool rewards!")
Sept. 16, 2023
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