First clear solution for Group Equal consecutive by erewhon - python coding challenges

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First solution in Clear category for Group Equal consecutive by erewhon

def group_equal(els):
    if els == []:
        return els

    separate = []
    for i in range(len(els)-1):
        if els[i] != els[i+1]:
          separate.append(i)

    start = 0
    result = []
    for s in separate :
        result.append(els[start:s+1])
        start = s+1
    result.append(els[start:])

    return result

Jan. 7, 2020

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