Simple clear solution for Ground for the House by thealfest1 - python coding challenges

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Simple solution in Clear category for Ground for the House by thealfest1

def house(plan):
    map = plan.split()
    minx = len(map[0])
    miny = len(map)
    maxx = maxy = 0
    for y in range(len(map)):
        for x in range(len(map[0])):
            if map[y][x] == '#':
                minx = x if x < minx else minx
                maxx = x if x > maxx else maxx
                miny = y if y < miny else miny
                maxy = y if y > maxy else maxy
    return 0 if minx == len(map[0]) else (1 + maxy - miny)*(1 + maxx - minx)

Jan. 9, 2019

Comments:

CGfrac on May 8, 2019, 8:09 p.m.
I'd return 0 right at the start of the function to save time, but other than that I'm digging the readability of your solution. Good job!

thealfest1 on May 9, 2019, 8:40 a.m.
This function returns area. We can`t return 0 until we know that area is actually 0.

CGfrac on May 9, 2019, 1:14 p.m.
Sorry I wasn't very clear. What I meant is that you can directly check whether '#' is in plan. If it's not then you just return 0 because no calculation is needed. Something like this: <pre class='brush: python'>if '#' not in plan: return 0 </pre> at the beginning of your function.

thealfest1 on May 9, 2019, 1:24 p.m.
I see.

Escher

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