OK, right after creative solution for Goes Right After by tom-tom - python coding challenges

Enable Javascript in your browser and then refresh this page, for a much enhanced experience.

OK, right after solution in Creative category for Goes Right After by tom-tom

def goes_after(word: str, first: str, second: str) -> bool:
    return word.find(first) + 1 == word.find(second) > 0

April 16, 2020

Comments:

SasuH on Jan. 11, 2021, 8:09 p.m.
Neat way to check -1s out.

Andrz on April 16, 2021, 12:10 p.m.
Very interesting! Can you explain why this part: '> 0' ?

tom-tom on April 16, 2021, 6:48 p.m.
Consider this: `goes_after('world', 'a', 'w')` <pre class='brush: python'>>>> 'world'.find('a') -1 >>> 'world'.find('w') 0 >>> -1 + 1 == 0 True >>> </pre>

viktor.chyrkin on Aug. 22, 2021, 2:26 p.m.
cool!

Mysta on Feb. 1, 2022, 7:18 a.m.
It's not only "Creative"! It's clear and easy, too! I like it!

Scientific Expedition

0 %

PyCharm The Python IDE for Professional Developers. Enjoy productive Python, web and scientific development with PyCharm. Download it now!